Question

What function best represents a sine function with an amplitude of 4, a period of π/6, and a midline at y = −2?

Answer 1

ampltude means it will be like y=4sinx

Answer 2

a. -2sin(x-π/6)+4
b. 4sin12x-2
c. 4sin(x-π/6)-2
d. -2sin12x+4

Answer 3

Asin(Bx-C)+D where A is the amplitude, period is 2pi/B, D is the midline. so it would be 4sin(12x)-2 since the period is pi/6, pi/6 = 2pi/B, we can simplify this out to B=12.

im 95% sure this is right. been a bit since ive done these.

Answer 4

since there is no C (C is the phase shift), dont worry about that part.

Answer 5

So it would definitely be b or c right? Because the amplitude is the first number?

Answer 6

id say its definitely 4sin12x-2, but try to actually learn how it works first...

Answer 7

Oh sorry I just saw that you put what you thought the answer was. Thank you so much!

Answer 8

when solving for B - 2pi/B = pi/6 (the period), we can multiply B by both sides get Bpi/6=2pi, then we divide both sides by pi/6. we get B= 6x2pi/pi, the pi's cancel out and were left with B=12.

Answer 9

when dealing with tan functions, the period is = pi/B rather then 2pi/B

Answer 10

Yeah.. Thanks for helping me with this problem!