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Mathematics 17 Online
OpenStudy (anonymous):

Find P(subject lied | negative results) P(negative results | subject lied) PLEASE HELP

OpenStudy (anonymous):

|dw:1407642148937:dw|

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

let's find P(subject lied | negative results)

jimthompson5910 (jim_thompson5910):

P(subject lied | negative results) means "the probability of the subject lying given it's a negative test result"

jimthompson5910 (jim_thompson5910):

so we're given "negative results" which means we don't even need to bother with the positive result we can even cross it out for the time being if you want

jimthompson5910 (jim_thompson5910):

we focus just on the "negative results" row |dw:1407642542714:dw|

jimthompson5910 (jim_thompson5910):

how many negative results are there total?

OpenStudy (anonymous):

38

jimthompson5910 (jim_thompson5910):

of those, how many lied?

OpenStudy (anonymous):

8

OpenStudy (anonymous):

ahh do i divide that?

jimthompson5910 (jim_thompson5910):

so the probability is 8/38 = 4/19

jimthompson5910 (jim_thompson5910):

So, P(subject lied | negative results) = 4/19

jimthompson5910 (jim_thompson5910):

do you see how to do the next one?

OpenStudy (anonymous):

is that the same process just dealing with the two lie numbers?

jimthompson5910 (jim_thompson5910):

what do you mean?

OpenStudy (anonymous):

the 41 and 8

OpenStudy (anonymous):

or is it both positive results numbers?

jimthompson5910 (jim_thompson5910):

I'm guessing you're onto P(negative results | subject lied) now?

jimthompson5910 (jim_thompson5910):

if so, then you focus on the "subject lied" column |dw:1407642960585:dw|

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