Question

find the equation of a circle with center at (-1,3) and passes through the point (2,-4)

Answer 1

@MrNood

Answer 2

shall i find their distance??

Answer 3

find the distance from the centre to the point, that will be the radius...

then the standard form is

\[(x - h)^2 + (y - k)^2 = r^2\]

(h, k) is the centre... so substitute your values

Answer 4

the distance gives you the radius.

Answer 5

\[\sqrt{58}\]

Answer 6

in this case you already have h and k

Answer 7

(x+1)^2 +(y-3)^2=58

Answer 8

yep

Answer 9

you have to calculate distance from point (2,-4) to (-1,3) by distance formula.....that will be your radius...
substitute in \[(x-h)^2 +(y-k)^2=r^2\], where (h,k)= (-1,3)