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OpenStudy (mokeira):
when you are asked to factor \[4x ^{2}-25\]
what immediately comes to mind is \[(a-b)(a+b)\]
So, what comes to mind when you are asked to factor:
\[x ^{3}-3x ^{2}-4x+12\]
OpenStudy (larseighner):
The coefficients suggest tying \(x \pm 3\) or \(x \pm 4\). As it happens, three of the four possibilities pay off.
OpenStudy (anonymous):
@ganeshie8 here question is right?
OpenStudy (anonymous):
this question will be solved by completing square as shown below
(2x)^2 -(5)^2
by applying this formula
a^2 - b^2=(a+b)(a-b)
=(2x+5)(2x-5)
OpenStudy (anonymous):
in the next question
\(x^3-3x^2-4x+12\)
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OpenStudy (anonymous):
by taking common
=\(x^2(x-3)-4(x-3)\)
=\((x^2-4)(x-3)\)
=\((x^2-2^2)(x-3\))
=\((x+2)(x-2)(x-3\))
OpenStudy (mokeira):
oooooh thnks!
OpenStudy (precal):
that is called factoring by grouping as nicely demonstrated by ziqbal103