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Mathematics 18 Online
OpenStudy (mokeira):

Factorization

OpenStudy (mokeira):

when you are asked to factor \[4x ^{2}-25\] what immediately comes to mind is \[(a-b)(a+b)\] So, what comes to mind when you are asked to factor: \[x ^{3}-3x ^{2}-4x+12\]

OpenStudy (larseighner):

The coefficients suggest tying \(x \pm 3\) or \(x \pm 4\). As it happens, three of the four possibilities pay off.

OpenStudy (anonymous):

@ganeshie8 here question is right?

OpenStudy (anonymous):

this question will be solved by completing square as shown below (2x)^2 -(5)^2 by applying this formula a^2 - b^2=(a+b)(a-b) =(2x+5)(2x-5)

OpenStudy (anonymous):

in the next question \(x^3-3x^2-4x+12\)

OpenStudy (anonymous):

by taking common =\(x^2(x-3)-4(x-3)\) =\((x^2-4)(x-3)\) =\((x^2-2^2)(x-3\)) =\((x+2)(x-2)(x-3\))

OpenStudy (mokeira):

oooooh thnks!

OpenStudy (precal):

that is called factoring by grouping as nicely demonstrated by ziqbal103

OpenStudy (mokeira):

how many types of factoring are there?

OpenStudy (mokeira):

@precal

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