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Mathematics 20 Online
OpenStudy (anonymous):

factor completely 7x^2-12xy+5y^2

OpenStudy (anonymous):

\(7x^2-12xy+5y^2\)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

1st of all we w'll take lcm by multiplying 5*7

OpenStudy (anonymous):

we get 35

OpenStudy (anonymous):

now we will add 5 and 7 in this way that we get negative 12xy

OpenStudy (anonymous):

-7xy -5xy = -12xy

OpenStudy (anonymous):

so \(7x^2-7xy-5xy+5y^2\)

OpenStudy (anonymous):

now take common \(7x(x-y)~-~5y(x-y)\) now factors are \((7x-5y)(x-y)\)

OpenStudy (anonymous):

@cessy18 get it?

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