Question

A rocket travels 50 km vertically upward at a 90° angle from point A to point B. It then moves a distance of 50 km along the line segment BC, as shown below:

ABCD is a trapezoid with AB equal to 50 kilometers and BC equal to 50 kilometers. A perpendicular to line CD is shown with a dashed line. This perpendicular passes through point B. The measure of the angle between BC and the perpendicular is 30 degrees.

What is the height of the rocket, at point C, from the ground?

90 km

75 km

80 km

85 km

Answer 1

@ganeshie8

Answer 2

use trigonometry..

sin 30 = opp/ hyp

opp = sin 30 * 60=30

and from given, its rectangle so that length is 60..

so pint c = 60 + 30 = 90 Km

Answer 3

i put the wrong picture.. my bad hold up

Answer 4

i had d diagram...newaz 90km is d ans

Answer 5

oh okay