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OpenStudy (anonymous):
Identify the oblique asymptote of f(x) = quantity x squared minus 4 x plus 8 over quantity x plus 2.
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OpenStudy (johnweldon1993):
The oblique asymptote will come from the long division
\[\large \frac{x^2 - 4x + 8}{x + 2}\]
|dw:1407715655355:dw|
OpenStudy (anonymous):
THANKS SO MUCH
OpenStudy (johnweldon1993):
No problem :)
OpenStudy (anonymous):
CAN YOU HELP ME WITH A NOTHER
OpenStudy (anonymous):
@johnweldon1993
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OpenStudy (johnweldon1993):
Yeah sure :)
OpenStudy (anonymous):
awesomeee
1 sec
OpenStudy (anonymous):
Identify the horizontal asymptote of f(x) = quantity x squared plus 5 x minus 3 over quantity 4 x minus 1.
OpenStudy (johnweldon1993):
Horizontal asymptotes happen when we see what the function equals when we let x go to infinity
OpenStudy (johnweldon1993):
so
\[\large \frac{x^2 + 5x - 3}{4x - 1}\]
If we plug in infinity here for 'x' we would essentially have
\[\large \frac{\infty^2}{\infty} = \infty\]
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OpenStudy (johnweldon1993):
Now we dont say this has a horizontal asymptote of infinity...we just say it doesn't have one
OpenStudy (anonymous):
oh. okay great thanks so much, i really appreciate it
OpenStudy (johnweldon1993):
Anytime!
OpenStudy (anonymous):
so for oblique asymptotes we do long division?
OpenStudy (johnweldon1993):
Right
Oblique = long division
Horizontal = plug in infinity for 'x' and simplify
Vertical = See what makes the denominator = 0
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OpenStudy (anonymous):
okay i sorta get it now
thanks thanks loads
OpenStudy (johnweldon1993):
If you have any more questions feel free to message me :)
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
@johnweldon1993
OpenStudy (anonymous):
What is the discontinuity of the function f(x) = the quantity of x squared minus 4 x minus 12, all over x plus 2?
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