Question

Solve for x on [0.2π)

Answer 1

more information needed

Answer 2

solve for x on [0,2π)
sin^2 x=sinx

Answer 3

Try to use this identity: \(\sin^2x=\dfrac{1-\cos(2x)}{2}\)

Answer 4

why?

Answer 5

if you use that identity you can simplify the equation so you can solve for x.

Answer 6

or do this sin^2x-sinx=0 ==> sinx(sinx-1)=0
now solve for x