Question

given that cos(x)=1/3, find sin(90-x)
please help!

Answer 1

\[\sin(90^o-x)=\cos(x)\]

Answer 2

im not exactly sure where to start on the equation :(

Answer 3

you are already informed that \(\cos(x)=1/3\).

Answer 4

Find x first,

\(\sf cos^{-1}(cos(x))=cos^{-1}(\dfrac{1}{3})\)

\(\sf x=cos^{-1}(\dfrac{1}{3})\)