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Mathematics 18 Online
OpenStudy (anonymous):

the probability that a male will be colorblind is 3.8%. What is the probability that at least one out of a group of 54 men will be colorblind?

OpenStudy (anonymous):

at least one translate as "not none"

OpenStudy (anonymous):

compute the probability that none are colorblind (that is easy) and subtract that number from one

OpenStudy (anonymous):

im really not too good at probabilities :/ @satellite73

OpenStudy (anonymous):

the probability any one is colorblind is \(.038\) the probability they are not is therefore \(1-.038=0.962\) the probability that all 54 are not is \[(.962)^{54}\] and so the probability that at least one is is \[1-(0.968)^{54}\]

OpenStudy (anonymous):

.8273?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

i don't know i didn't do it

OpenStudy (anonymous):

did you mean to put .968?

OpenStudy (anonymous):

your answer is right

OpenStudy (anonymous):

sweet thank you again!

OpenStudy (anonymous):

oh wait hold on

OpenStudy (anonymous):

was it supposed to be .962?

OpenStudy (anonymous):

should be \(1-(0.962)^{54}\)

OpenStudy (anonymous):

i made a typo i think

OpenStudy (anonymous):

okay so i got .8766 this time!

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=1-%280.962%29^ {54}

OpenStudy (anonymous):

yeah that looks good

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

yw

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