the probability that a male will be colorblind is 3.8%. What is the probability that at least one out of a group of 54 men will be colorblind?
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OpenStudy (anonymous):
at least one
translate as "not none"
OpenStudy (anonymous):
compute the probability that none are colorblind (that is easy) and subtract that number from one
OpenStudy (anonymous):
im really not too good at probabilities :/ @satellite73
OpenStudy (anonymous):
the probability any one is colorblind is \(.038\)
the probability they are not is therefore \(1-.038=0.962\)
the probability that all 54 are not is
\[(.962)^{54}\] and so the probability that at least one is is
\[1-(0.968)^{54}\]
OpenStudy (anonymous):
.8273?
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OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
i don't know i didn't do it
OpenStudy (anonymous):
did you mean to put .968?
OpenStudy (anonymous):
your answer is right
OpenStudy (anonymous):
sweet thank you again!
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OpenStudy (anonymous):
oh wait hold on
OpenStudy (anonymous):
was it supposed to be .962?
OpenStudy (anonymous):
should be \(1-(0.962)^{54}\)
OpenStudy (anonymous):
i made a typo i think
OpenStudy (anonymous):
okay so i got .8766 this time!
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