Question

what is d/dx {(x^2 + 2) + (x-1)^.5}/(x^2+3x-1)

Answer 1

are u trying to simplify it

Answer 2

yes

Answer 3

\[\huge \color{green}{\textsf{Welcome To Openstudy...}}\]

Answer 4

@maithili
\(\Huge\bf \color{yellow}{Welcome~to~OpenStudy!!}\hspace{-310pt}\color{cyan}{Welcome~to~OpenStudy!!}\hspace{-307.1pt}\color{midnightblue}{Welcome~to~\color{purple}{Open}}\color{blue}{Study!!!!}\)
Ughgh..Steeler. Just Kidding:)

Answer 5

quotient rule ?

Answer 6

ok then hold on

Answer 7

roise, to derive, not simplify.

Answer 8

ok

Answer 9

I did try it but not sure of my answer

Answer 10

What are you getting?

Answer 11

what did u get

Answer 12

it is something long and retarded.

Answer 13

i was asking @maithili

Answer 14

Hahahha!!! @SolomonZelman

Answer 15

it is basically just lots of work. quotient and power rule.

Answer 16

draw it, that's easier.

Answer 17

{2x^3+6x^2 - 2x +.5{x^2 + 3x-1/[x-1]^.5} -2x^3 - 4x - 2x{x-1}^.5 - 3x^2 -6 -3{x-1}^.5 } / x^4 + 6x^3 -7x^2- x +1

Answer 18

lol..yes..long and retarded

Answer 19

ugh, an exercise in futility ....

Answer 20

you can reduce that answer--but it looks right

Answer 21

yea what @agreene said

Answer 22

it does?...phew...I could reduce it a bit i guess

Answer 23

I am getting, without expanding or reducing,

[ 2x+ {1 / 2√[x+1] } ] (x²+3x+1) - (2x+3)(x²+√[x-1] + 2 )
--------------------------------------------------
x²+3x-1

Answer 24

(2x+3)(x²+√[x-1] + 2 )
[ 2x+ {1 / 2√[x+1] } ] - -------------------------------
x²+3x-1

Answer 25

squared on the denominator

Answer 26

Oh.this is better..let me try your way

Answer 27

Yes, square on the denominaotr. my bad

[ 2x+ {1 / 2√[x+1] } ] (x²+3x+1) - (2x+3)(x²+√[x-1] + 2 )
--------------------------------------------------
( x²+3x-1 ) ²

Answer 28

[ 2x+ {1 / 2√[x+1] } ] (2x+3)(x²+√[x-1] + 2 )
-------------------- - ------------------------------
( x²+3x-1 ) ( x²+3x-1 ) ²


or leave it without re-writing it as 2 fractions.

Answer 29

thanks alot :)..really helped

Answer 30

They should have given you a problem, where you can demonstrate your knowledge, but without any pain.

Answer 31

yw, if I helped....

Answer 32

my teacher only gave us these kind of problems :'(

Answer 33

but yeh: remember \[\frac{d}{dx}\frac{f(x)}{g(x)}=\frac{g(x)f'(x)-f(x)g'(x)}{g(x)^2}\]

Answer 34

yes...thanks for the tip

Answer 35

I guess you guys started from a more clear ones, or you should have started from more clear ones.
First comes the more clean, and then the dirty stuff.

And yes, agreene to the rescue :)

Answer 36

my answer matched yours..phew

Answer 37

we did a few easy ones and then we were bombarded with this :P