Write an equation in slope-intercept form of the line that passes through the points (-2,-1) and (3,5).
@TylerD
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -2}}\quad ,&{\color{blue}{ -1}})\quad &({\color{red}{ 3}}\quad ,&{\color{blue}{ 5}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)
\[\frac{ 5-(-1) }{ 3-(-2) }\]
M = \[\frac{ 6 }{ 5 }\]
\[y-(-1)=\frac{ 6 }{ 5 }(x-(-2))\] \[y+1=\frac{ 6 }{ 5 }x+\frac{ 12 }{ 5 }\] the finaly subtract 1 from both sides we get \[y=\frac{ 6 }{ 5 }x+1.4\]
when you subtract a negative it becomes + thats why y-(-1) becomes y+1
same for the x-(-2) it becomes x+2 2 times 6/5 = 12/5
Write an equation of a line that is perpendicular to y = 2x + 3 and passes through (3,4).
thk u so much Tyler just a few more n ill b done
so perpendicular lines are lines that form a right angle (90 degrees) where they intersect
so if our slope is M=2 a slope for the perpendicular line would be M=-0.5 so the slope is the negative reciprocal reciprocal of 2 = 1/2 make it negative -1/2
hmmmm interesting keep goin Tyler
y=-0.5x+3 is perpendicular to y=2x+3
wait
did not notice it says passes through (3/4)
er (3,4)
so in this case we have to solve y=-0.5x+b
yes I c that
4=-0.5(3)+b 4=-1.5+b b=5.5
hmmmm interesting
so the solution is y=-0.5x+5.5
can u help with my math @mathkid10
im here u just c meh
*cant
@TylerD pls help meh *~*
my internet is actin up again
close and start a new
ok
sure
Join our real-time social learning platform and learn together with your friends!