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Mathematics 24 Online
OpenStudy (cydney_morgan):

What are the missing measures? (pic below) forty-eight degrees, one hundred ninety-two degrees sixty degrees, two hundred forty degrees eighty degrees, three hundred twenty degrees one hundred eighty-eight degrees, forty-seven degrees

OpenStudy (cydney_morgan):

OpenStudy (cydney_morgan):

Ok so I did 105 + 130 + 120 + 125 = 480

OpenStudy (cydney_morgan):

And now I do 4x divided by 480 right?

OpenStudy (abhisar):

Sum of angles of a polygon = 180(n-2) Where n is the number of sides

OpenStudy (cydney_morgan):

There is no 'n' only two x'es though. ;;

OpenStudy (abhisar):

The polygon in the figure has 6 sides and is a hexagon So, Sum of its all angles will be equal to 720 Now, 480+5x=720 =>5x=240 =>x=240/5=48°

OpenStudy (abhisar):

wait ! let me elaborate it a lill more

OpenStudy (abhisar):

The figure is hexagon...ryt ?

OpenStudy (cydney_morgan):

Uhm, Yes, it has 6 sides.

OpenStudy (abhisar):

What will be the sum of its all angles ?

OpenStudy (cydney_morgan):

Um.. 720?? I think?

OpenStudy (abhisar):

yes..but how can u say that ?

OpenStudy (cydney_morgan):

I don't know D: I'm really confused, like, how did you find that out??

OpenStudy (abhisar):

You can use this formula \(\color{blue}{\text{Originally Posted by}}\) @Abhisar Sum of angles of a polygon = 180(n-2) Where n is the number of sides \(\color{blue}{\text{End of Quote}}\) Sides in a hexagon is 6, so 180(6-2)=720

OpenStudy (abhisar):

Got it ?

OpenStudy (cydney_morgan):

OHHH i get that.

OpenStudy (midhun.madhu1987):

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OpenStudy (abhisar):

Now just make an equation 130+120+125+105+4x+x=720 =>5x+480=720 =.5x=240 =>x=240/5 =>x=48

OpenStudy (cydney_morgan):

Ohhh but were did you get the 5x??

OpenStudy (abhisar):

x+4x=5x

OpenStudy (cydney_morgan):

OHHH

OpenStudy (midhun.madhu1987):

So, we can derive an equation connecting the number of sides and total angle: Total angle of a Polygon with n sides = (n-2) x 180

OpenStudy (abhisar):

@Cydney_Morgan Have u learned solving problems on linear equations ?

OpenStudy (cydney_morgan):

No, not at all.

OpenStudy (abhisar):

Hmmm..let me find something for ya

OpenStudy (cydney_morgan):

Ok, thank you for teaching me!

OpenStudy (abhisar):

http://www.purplemath.com/modules/solvelin.htm This might help u !

OpenStudy (cydney_morgan):

Oh ok! I see! I know how to do that, I just did not know thats what they were called.

OpenStudy (abhisar):

oh..i see ! So 4x+x =5x 4x+6x= ?

OpenStudy (cydney_morgan):

Were did you get the 6 from??

OpenStudy (abhisar):

I am just asking u...a separate question..

OpenStudy (cydney_morgan):

OHH ok I see :D Give me a moment.

OpenStudy (cydney_morgan):

10x??

OpenStudy (cydney_morgan):

Is that wrong?

OpenStudy (abhisar):

yes it's correct..but that's too much time u took :(

OpenStudy (cydney_morgan):

I'm sorry, I got confused for a moment. :c I thought I needed to find out what 10x was. :/

OpenStudy (abhisar):

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar 5x+5x=100 => x= ? \(\color{blue}{\text{End of Quote}}\)

OpenStudy (cydney_morgan):

10x = 100?? But I need to find out what x is right?

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