-3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points) Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)
do you know how to do this @Mokeira ?
@aajugdar help
oh hey you have to create two new equations
one by adding -3x + 7y = -16 and -9x + 5y = 16 and second by multiplying -3x + 7y = -16 and -9x + 5y = 16
do i just add the x's and y's together
yeah
-3x + 7y +(-9x + 5y) = -16+16
ok thank and how do i do part b
in 2nd you have to solve original two equations as well as new equations and you have to show that values of x and y match in both systems of equations
i don't know how to solve it
@aajugdar
oh? hmm okay i will help
-3x + 7y = -16 -9x + 5y = 16 so you have two equations here there are many ways to solve this but i will tell you elimination method okay?
okay
in elimination method what you have to do is either eliminate x compnent or y component so in the equations -3x + 7y = -16 -9x + 5y = 16 suppose we want to eliminate x component now we have -3x and -9x as x components so we multiply first equation by -3 in order to eliminate those so you get -3(-3x+7y=-16) 9x-21y=48
so now you have two equations 9x-21y=48 and -9x + 5y = 16
now add these two equations 9x and -9x will be canceled -21y+5y = -16y 48+16=64 so we get -16y = 64 so y= 64/-16 y= -4
now consider this equation -9x + 5y = 16 we know that value of y is -4 put this value in equation -9x+5(-4) =16 -9x-20=16 -9x=36 x=-4 so you have values of x and y by elimination method any doubts?
thanks a lot helped me very much!!!!!!!!!
you are welcome :)
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