Question

If sin Θ = negative square root 3 over 2 and π < Θ < 3 pi over 2, what are the values of cos Θ and tan Θ?

Answer 1

Do you know how to simplify?

Answer 2

This lesson doesn't really make any sense to me.

Answer 3

Does this help you any? Its an example~ :D



(sinx - cosx)^2 - (sinx + cosx)^2
= (sin^2 x - 2sinxcosx + cos^2 x) - (sin^2 x + 2sinxcosx + cos^2 x)
= - 2 sinx cosx - 2 sinx cosx
= - 4 sinx cosx
= - 2sin(2x)

sin(2pi/3) = sqrt(3)/2

Answer 4

Eh, a little bit. I have the rations for sin, cos, and tan, idk if I would use it though

Answer 5

ratios*

Answer 6

Yes you should use.

Oh and if I helped you medal and fan please?

Answer 7

Sure.

Answer 8

Anybody else can help/guide me through this question?

Answer 9

I think it's A, but idk, anyone?

Answer 10

@gamer56, could it be a?

Answer 11

First of all,I cant see your answer choices

Answer 12

O, lol

Answer 13

cos Θ = negative 1 over 2; tan Θ = square root 3

cos Θ = negative 1 over 2; tan Θ = −1

cos Θ = square root 3 over 4; tan Θ = −2

cos Θ = 1 over 2; tan Θ = square root 3

Answer 14

:D

Answer 15

So, is it A or...

Answer 16

Alright, it is A, thank you @gamer56!

Answer 17

@flashy32 welcome fan and medal please?