Question

What is the domain of the following function?

f(x) = √-x - 1- 3
f(x) ≤ -1 x ≤ 1
f(x) ≤ 1 x ≤ -1

Answer 1

which part is in root

Answer 2

all of it. -x-1-3 i s in root

Answer 3

\(\normalsize\color{blue}{ f(x)=\sqrt{-x-1}-3}\)

Answer 4

The domain can be any real number that is less than or equal to -1, so that you don't get an imaginary in the square root.

Answer 5

she says the whole thing is in root

Answer 6

It can not be, it is silly to say \(\normalsize\color{blue}{ f(x)=\sqrt{-x-1-3}}\)

Answer 7

It should be, \(\normalsize\color{blue}{ f(x)=\sqrt{-x-1}-3}\)

Answer 8

And for that, domain ≤ -1

Answer 9

*shrugs*

Answer 10

so f(x) =sqrt -x -1-3
f(x) = sqrt -x -4
and f(x) =-1
okay
left hand side is same so compare right hand side
-1=sqrt -x -4
now square on both sides
1 = -x -4
x=-4-1
x=-5 is yur domain of this function
and again do it with f(x)=1 okay ?

Answer 11

I want to hear from the asker what the question is exactly like.

Answer 12

that is sooooooo soooo soooooooo wrong @Haseeb96

Answer 13

\(\normalsize\color{blue}{ f(x)=\sqrt{-x-1}-3}\) Domain ≤ -1

\(\normalsize\color{blue}{ f(x)=\sqrt{-x-1-3}}\) Domain ≤ -4

Answer 14

By the way guys,

1) Click and hold ALT

2) click the number code
(using the numbers that are on
the right of the keyboard, and `NOT`
the ones below `F1`, `F2`, `F3`, etc., )

3) release the ALT

number code result
` 2 5 1 ` √
`0 2 1 5 ` ×
`2 4 6 ` ÷
`7 5 4 ` ≥
`7 5 5` ≤
`2 4 1 ` or `7 5 3` ±
`2 4 7` ≈
`0 1 8 5 ` ¹
`2 5 3 ` ²
`0 1 7 9 ` ³

Answer 15

®

Answer 16

omg really i look away for a couple mins and i come back to this? lol its -1. end of discussion. thank you everyone.

Answer 17

hes kinda a retrice

Answer 18

haha retrice

Answer 19

haha it changes butt cuss word into retrace.. lol

Answer 20

No it is -1, or anything that is less than -1. Assuming that you meant \(\normalsize\color{blue}{ f(x)=\sqrt{-x-1}-3}\) initially.