Question

Help please, trig- is really hard

Answer 1

What are the amplitude, period, phase shift, and midline of f(x) = −4 cos(3x − π) + 1?

Answer 2

f(x) = -  4 cos(3x – π)  +  1   ...   in this form the characteristics are:

amplitude = 4

period = 2π ⁄ 3

phase shift = -π radians

vertical shift = +1

average = +1   =   midline

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HOWEVER, because of the -π phase shift, this equation is equivalent to:

y = 4 cos(3x)  +  1   ...   and in this form the characteristics are:

amplitude = 4

period = 2π ⁄ 3

phase shift = 0

vertical shift = +1

average = +1   =   midline

https://answers.yahoo.com/question/index?qid=20131104184948AA7nuoE

Answer 3

Are you sure? The phase shift doesn't match my options

Answer 4

I think.

Lets see if @paki can help

Answer 5

@paki @acxbox22

Answer 6

btw wut r ur answer choices @morningskye123

Answer 7

wait guys, isn't the function reflected ? Like you look at it, and you flip it upside down because of the minus in front of the 4?

Answer 8

Amplitude: −4; period: pi over 3; phase shift: x = pi over 4; midline: y = −1

Amplitude: 4; period: pi over 3; phase shift: x = pi over 4; midline: y = 1

Amplitude: −4; period: 2 pi over 3; phase shift: x = pi over 3; midline: y = −1

Amplitude: 4; period: 2 pi over 3; phase shift: x = pi over 3; midline: y = 1

Answer 9

@SolomonZelman

Answer 10

do is the answer C?

Answer 11

@ganeshie8 can you please help?

Answer 12

Yes its c