Question

For all x =(equal sign is crossed out)8,x^2-11x+24/8-x

Answer 1

\[\frac{x^2-11x+24}{8-x}=\frac{(x-8)(x-3)}{8-x}=-\frac{(x-8)(x-3)}{x-8}\]
When \(x\not=8\), we can eliminate the factor of \(x-8\), leaving you with \(-(x-3)=3-x\).

Answer 2

I'm confused...

Answer 3

How did you get you get that

Answer 4

Factored the numerator, then factored a -1 from the denominator:
\[\text{numerator: }x^2-11x+24=(x-8)(x-3)\\
\text{denominator: }8-x=-1(-8+x)=-(x-8)\]
Then the factors of \(x-8\) cancel out, leaving you with \(-(x-3)=3-x\).