Question

How in the world am I supposed to solve this??
@SolomonZelman do you know??

Answer 1

is it two pair?

Answer 2

Yes.

Answer 3

Like, would I multiply the 5 and 52??

Answer 4

i think it is
\[\frac{\binom{13}{2}\binom{4}{2}\binom{4}{2}\times 11\times 4}{\binom{52}{5}}\] let me check

Answer 5

Ok.

Answer 6

it is repeated applications of the counting principle
the denominator is the number of ways to pick 5 cards out of 52, i.e. the number of elements of your sample space

Answer 7

the numerator
\[\binom{13}{2}\] there are 13 values and you are picking two of them (like day jacks and eights)

Answer 8

\[\binom{4}{2}\] once a value is chosen say jacks, there are 4 jacks, you have a choice of two

Answer 9

\[\binom{4}{2}\] same argument for the other value (say eights)

Answer 10

\[4\times 11=44\] the number of possibilities for the last card
note that it cannot be of the same value as the two chosen, so maybe calling this \(52-8=44\) makes more sense

Answer 11

you want to compute this number \[\frac{\binom{13}{2}\binom{4}{2}\binom{4}{2}\times 11\times 4}{\binom{52}{5}}\] i would use wolfram
better yet i bet if you google the question you can find an answer, although unfortunately it is probably in decimal form

Answer 12

I used a different website and it gave me 1320/13

Answer 13

actually it is not that bad since four choose two is six
lets try this
\[\frac{\binom{13}{2}\times 36\times 44}{\binom{52}{2}}\]

Answer 14

lol that number you wrote is the probability of nothing

Answer 15

http://www.wolframalpha.com/input/?i=%28%2813+choose+2%29*44*36%29%2F%2852+choose+5%29

Answer 16

Lol, I know:) I just wanted to let ya knowXD. Give me a sec. Do you really recommend Wolf just about for anything? Lol!!

Answer 17

yes

Answer 18

i don't see your answer listed, but it looks like your choices were not reduced fractions

Answer 19

So what would I do?XD

Answer 20

i don't know i am not getting any of the answer choices
the question is cut off
we did just "two pair" and i am certain it is right
is there a part i cannot see?

Answer 21

Oh, Sorry..Let me take the screenshot. I'm sure we'll come out to the same answer though.

Answer 22

ok first of all
\[\binom{52}{5}=2,598,960\]

Answer 23

none of the above

Answer 24

google it
it is a common problem

Answer 25

Well then..I guess I'll let my teacher know.

Answer 26

Ok:) Lets see what I getXD.

Answer 27

really you will find lots of results
poker is very popular

Answer 28

here is one worked out
has all the poker hands i think

Answer 29

Ok:) I guess I'll have to guess on it then. But I really do appreciate all your help!!!! Trying to help me out!! Thank you!!!!

Answer 30

@satellite73 the answer was A!!:)