Question

Dividing Radicals

Answer 1

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Answer 2

@robtobey

Answer 3

\[ \large \frac{\sqrt{6x^2}}{\sqrt{4x}}=\frac{\sqrt{6}\sqrt{x^2}}{\sqrt{4}\sqrt{x}}=\frac{\sqrt{6}|x|}{2\sqrt{x}}\]
Now the denominator can't be equal to 0, so \(2 \sqrt{x} \ne 0\), and furthermore, we require \(\sqrt{x}\) have only non-negative values for x. Combining these two conditions, we get that the domain is all \(x > 0\)

Answer 4

\[\bigstar THANK~YOU~VERY~MUCH \bigstar\]

Answer 5

so D right?

Answer 6

yw :)

Answer 7

yes

Answer 8

xD i loved your simple explanation.

Answer 9

awesome =]