Question

http://prntscr.com/4ck5xb

Answer 1

@kirbykirby

Answer 2

@JoannaBlackwelder

Answer 3

@tejasvir

Answer 4

This looks like a simplification problem to me. Can you try to simplify the radicals?

Answer 5

Try writing the arguments of the radicals as a product of a perfect square and some other number

Answer 6

3 for \[\sqrt{27x}\]

Answer 7

Show me what you mean.

Answer 8

i simplified \[\sqrt{27x}\]

Answer 9

\(\sqrt{27x}=\sqrt{3*9x}=\sqrt{3}\sqrt{9}\sqrt{x}\)

Answer 10

ok

Answer 11

then \[\sqrt{48}\]

Answer 12

\(\sqrt{16*3}=4\sqrt{3}\)

Answer 13

and \(\sqrt{9}=3\), so \[\frac{3\sqrt{3}\sqrt{x}}{4\sqrt{3}}=\frac{3\sqrt{x}}{4} \]