What is the ∆G for the following reaction under nonstandard conditions where the following data is given? 2NH4Cl(s) + CaO(s) CaCl2(s)+ H2O + 2NH3(g) Given: CaO: ∆Hf = -635.09 kJ, ∆Sf =39.75 J/K CaCl2: ∆Hf = -795.8 kJ, ∆Sf =104.6 J/K. NH3: ∆Hf = -46.11 kJ, ∆Sf = 192.45, H2O: ∆Hf = -285.830 kJ, ∆Sf = 69.91 , NH4Cl: ∆Hf = -314.43 kJ, ∆Sf = 94.6 Update : A. 2.27 J B. -4.54 J C. 4.54 J D. 9.08 J E. -9.08 J

Question

What is the ∆G for the following reaction under nonstandard conditions where the following data is given?  2NH4Cl(s) + CaO(s) CaCl2(s)+ H2O + 2NH3(g)   Given:  CaO: ∆Hf = -635.09 kJ, ∆Sf =39.75 J/K  CaCl2: ∆Hf = -795.8 kJ, ∆Sf =104.6 J/K.  NH3: ∆Hf = -46.11 kJ, ∆Sf = 192.45,  H2O: ∆Hf = -285.830 kJ, ∆Sf = 69.91 ,  NH4Cl: ∆Hf = -314.43 kJ, ∆Sf = 94.6 Update : A. 2.27 J  B. -4.54 J  C. 4.54 J  D. 9.08 J  E. -9.08 J

anonymous · Answer

Does anyone understand this or know this answer - would greatly appreciate help!!!

joannablackwelder · Answer

Do you know T?

anonymous · Answer

No, this is all we got.

anonymous · Answer

If you had to pick one that made most sense, which one would you go with?

joannablackwelder · Answer

Wow, that is a lot of numbers to work through to try to make an educated guess. It looks like you need to work through a process similar to example 1 at http://chemwiki.ucdavis.edu/Physical_Chemistry/Thermodynamics/State_Functions/Free_Energy/Gibbs_Free_Energy/Gibbs_Free_Energy

joannablackwelder · Answer

But you will need temp.

joannablackwelder · Answer

So......

joannablackwelder · Answer

idk

anonymous · Answer

Yeah that what I thought.  Thanks!!

joannablackwelder · Answer

No worries

joannablackwelder · Answer

Welcome to Open Study!

anonymous · Answer

Thanks - my one thought was to go with 2.27 because the other choice are positive & negatives of 2 different numbers and 2.27 was different from the choices I have to choose from.

joannablackwelder · Answer

Yeah, that makes me think that it isn't 2.27...

anonymous · Answer

I know because usually on multiple choice if they are similar they it's one of them.  I will just have to guess something because I really don't know how to calculate.

joannablackwelder · Answer

Yeah, me neither. Sorry. @abb0t  might be able to help, but he's not online right now.

anonymous · Answer

Thanks again!!

anonymous · Answer

@abb0t  - can you help me with this question.  The question did not give temperature. Thanks!