Question

http://gyazo.com/5b606dedc418033ff386920fb4f9c9f2

@satellite73 Can you tell me the answer please... And explain it while you are doing it.

Answer 1

\[\cot(\theta)=\frac{9}{2}\]

Answer 2

the hypotenuse is
\[\sqrt{9^2+2^2}=\sqrt{85}\]

Answer 3

but... isnt the problem talking about a circle?

Answer 4

it is asking for the sine of an angle whose cotangent is \(\frac{9}{2}\)

Answer 5

from the triangle you see that the sine is two over root 85
i.e.
\[\sin(\theta)=\frac{2}{\sqrt{85}}\]

Answer 6

since you are in quadrant 2, sine is positive

Answer 7

oh alright i understand.

Answer 8

k good

Answer 9

thanks <3

Answer 10

umm.. ok i understand what u did but... what do i enter in my calculator tho to get the answer?

Answer 11

Let me look at your problem then I will tell you ok?

Answer 12

sure

Answer 13

Actually you don't need a calculator to figure this out, per se. First of all, realize that cot is the cofunction for tangent and if cotangent of an angle is -9/2, then the tangent of it is -2/9. Got that so far?

Answer 14

you don't enter anything in your calculator

Answer 15

unless you want to convert
\[\frac{2}{\sqrt{85}}\] to a decimal
otherwise just leave it

Answer 16

And in the second quadrant it looks like this:

Answer 17

to find the sin of that angle, you have to find x, which is the hypotenuse of the right triangle.