Question

How many liters of oxygen gas, at standard temperature and pressure, will react with 35.4 grams of calcium metal? Show all of the work used to solve this problem.

2 Ca + O2 ---> 2 CaO

Answer 1

This one is pretty similar.Can you see how far you can get?

Answer 2

Ok so we are gonna use the same formula right?

Answer 3

You got it.

Answer 4

Standard temp = 273K Standard Pressure= 1atm

Answer 5

PV=nRT P=1 R=0.0821 T=273

Answer 6

Pretty close to 1 atm. It is technically 1 bar which is 0.987 atm, but close enough.

Answer 7

Ok and would n= 2?

Answer 8

I don't get that.

Answer 9

I dont know what to do from here

Answer 10

Use the grams of Ca to get moles of Ca.

Answer 11

35.4 g Ca*(1 mol/40 g Ca)=.885 mol Ca

Answer 12

ohh ok

Answer 13

.885 mol Ca*(1 mol O2/2 mol Ca)=

Answer 14

0.4425 mol O2

Answer 15

.4425/1.77?

Answer 16

What does that get?

Answer 17

.25 Would that be n?

Answer 18

Why did you divide by 1.77?

Answer 19

because if one mol of Ca=.885 and you have two that would be 1.77mol right?

Answer 20

One mole of Ca isn't .885. You have .885 moles of Ca is what we have to start with.

Answer 21

Yeh im sorry im getting confused

Answer 22

so would it just be .4425/.885

Answer 23

Now I'm confused why you would do that...

Answer 24

ok lets star from = .885 mol Ca*(1 mol O2/2 mol Ca)=

Answer 25

There you go!!! :D

Answer 26

How many moles of O2 is that?

Answer 27

Just one?

Answer 28

Why?

Answer 29

I dont know thats as far as i can go

Answer 30

.885 mol Ca*(1 mol O2/2 mol Ca)=0.4425 mol O2

Answer 31

You had it, you just didn't simplify.

Answer 32

Ok but can you explain how you got 0.4425 mol O2

Answer 33

.885 mol Ca*(1 mol O2/2 mol Ca) means you take 0.885 *1/2=0.4425

Answer 34

Ohhhhh ok i got it

Answer 35

mol Ca*mol O2/mol Ca = mol O2 :)

Answer 36

Yay!

Answer 37

so now we have n right?

Answer 38

You got it!

Answer 39

P=1 R=0.0821 T=273 n=4425 V=x

Answer 40

n=0.4425

Answer 41

right sorry

Answer 42

No worries :)

Answer 43

V=9.917?

Answer 44

That's what I get :)

Answer 45

awsome

Answer 46

in Liters

Answer 47

Yup!

Answer 48

Ok im getting it now just need two more

Answer 49

No.. This is not a practice exam. This is a module quiz from FLVS so using this answer will be an academic integrity violation. Plus it has a obvious mistake in it.

Mr. Carlyle
FLVS Chemistry Instructor

This question is a violation of the OpenStudy Guidelines. The question is from an online school plus a violation by solicitation for members to unknowingly assist them cheating on an exam. 30653065chem30653065