Question in next comment!
must be a hell of a question
okay i have a current mudoled by the following function \(\Large \sf\color{blueviolet}{I(t)=5e^{-2t}sin(t)}\) we need to approximate the current after t=0.7 seconds in amperes this is was in the exam, i did the calculation in degrees i got I=0.015 amperes. Problem is i realized that i did wrong and it should be in radians
No just simple! i just need verification!
i was so darn angry after the test hehe i was sure to get full credit! but i realized i didn't pay attention to this
@satellite73 what do you think
i have no idea what this is sorry
hah lol
i do know that if you are using sine as a function, it is a function of numbers, not radians or degrees or dollars of euros of fahrenheit or celsius as such it does correspond to a function of angles, but only if the angles are measured in radians
the current i got using radians is I=0.73 amperes
you wrote \[\Large \sf\color{blueviolet}{I(t)=5e^{-2t}sin(t)}\]but \(t\)i s supposed to represent time right?
okay! well basically that's what i did!
yes t corresponds to time in seconds
time is neither radians nor degrees, nor parsecs or milligrams
ooh i see you had your calculator is "degree" mode right?
that is what im talking about^_^ you got me
oops
i think my answer was wrong comparing the two currents i got should be set to radians mode hehe
prolly
Darn it all! hehe i was so confident to get this^_^
Well thanks
i hope im wrong lol
about this
@ganeshie8 what do you think
should to the result be under degree mode or radian mode that is my curiosity
radian mode
question : how do you know \(t\) is in seconds and not hours/years ?
the question stated t=0.7 seconds
that is damped harmonic oscillation, though the argument of the sine function has been simplifed to just t (missing 2Pi f) and the time is almost always in seconds with this stuff because seconds are SI units
it said what the current would be after 0.7 seconds
would you assume \(t\) is in hours if it asks to compute current after 0.7 hours ? :)
you always assume t is in seconds if given no other information. the reason is because this equation is a form of commonly encountered equation, again, one of damped harmonic motion. This is commonly found in RLC circuits
do you say \(\omega t= 2\pi ft\) or \(\omega = 360ft\) ? i think it depends actually, but radians/second is what we use in engineering,,, and it should be easy to figure out based on context
you will still need to convert to second like inky said
@ganeshie8 I am merely being practical. The units of equations are not always labelled, and when they are not, certain assumptions are usually made about them.
I agree with you on that, I am an engineer myself :) my question was to answer @xapproachesinfinity 's question on why we use radians
I haven't practiced circuit in a long time so i can't remember what this stuff is about hehe
strictly speaking, the question must specify \(t\) is in seconds and \(\omega\) is in radians/second so that the student is not confused. however nobody add that info because the question becomes unnecessarily lenghty and almost all the time students use correct units without even thinking.
the question didn't mention anything beside that t is in seconds this was a precalc question not physics!
lazy professor :P consider distance funciton : \[d=5t\] If I ask you to compute the distance travelled after 5 minutes, is it proper to assume that t is in minutes ? the actual units of function could be in seconds or hours, right ?
Agree with that!
to clear the ambiguity, you must ask me two questions back: 1) what are the units of time ? 2) what are the units of distance ? (or) what are units of speed ?(not shown using variable)
you cannot compute distance travelled in 5 minutes without knowing above contextual info ^^
I agree with that!
again, we should not complain too much haha! your professor is the boss and you will get use to ur professor and subject over time and care less about these petty stuff ;)
haha, correct! let's leave at that will ask the prof later about it^_^ thanks guys
hmm , yeah before asking there is something maybe could help which is the unity of units lol (idk what its called in english ) what i mean is there is standerd unit that we get used to use them together (usually been mintioned in ut apendex txt book ) like :- (velocity ) km/h , ,mile /h , m /sec
well that won't help though hehe cuz we know we should use seconds SI unit for t is seconds for the current I SI unit is ampere ======= the test mentioned t in seconds so you have to stick with that my question was about when evaluating t=0.7 should i do that under radian mode or degree mode ganesh mentioned something about angular speed being in radian/second don't if you need to use this fact or not i think for this question you just need to evaluate the 0.7! the only issue here is whether we have to use degree mode or radian mode in the calculator
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