Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <8, 7>, v = <9, 7>

Answer 1

use dot product
\[\Large u.v=|u|*|v|*\cos \theta\]

Answer 2

First, find \(a\cdot b\) using the method I just showed you in your previous question, then use the formula
\[a\cdot b = |a||b|\cos\theta\], where |a| = \(\sqrt{(a_1)^2+(a_2)^2}\), and similar for |b|

Answer 3

u and v can be expressed as
\[u=8 \hat i+7 \hat j \\v=9 \hat i+7 \hat j\]

Answer 4

now can u find
\[u.v=?\]

Answer 5

the lines by the letters, what do they mean?

Answer 6

\[<a,b,c> they ~can~be~expressed~as \\a \hat i +b \hat j+c \hat k\]
like this

Answer 7

or u can keep them as they are now can u find out first (u.v)

Answer 8

\[u.v=<8,7>*<9,7>=8*9+7*7=72+49=121 \\ok???\]

Answer 9

i knew that but that is not what im looking for

Answer 10

so which part ure not getting?

Answer 11

now
you just need to evaluate ,|u| and |v|
can u do that?