Question

How to compare these really need help

Answer 1

\[\sqrt{13}-\sqrt{12} , \sqrt{14}-\sqrt{13}\]

Answer 2

@Kainui help please

Answer 3

What do you mean, like, which is greater?

Answer 4

yes

Answer 5

Hmm, I guess my first guess is to try to rewrite them kind of like this, but I'm not sure if that's helpful: \[\LARGE 13-12=(\sqrt{13}-\sqrt{12})(\sqrt{13}+\sqrt{12})\]

Answer 6

Actually yeah that will help a lot!

Answer 7

How is that going to help , not getting any idea

Answer 8

oh!

Answer 9

how

Answer 10

\[\LARGE \frac{1}{\sqrt{13}+\sqrt{12}}=\sqrt{13}-\sqrt{12}\] This is true correct? Now let's look at the other one, it's just \[\LARGE \frac{1}{\sqrt{14}+\sqrt{13}}=\sqrt{14}-\sqrt{13}\] Since there is only addition in the denominator, we know that \[\LARGE \frac{1}{\sqrt{13}+\sqrt{12}}>\frac{1}{\sqrt{14}+\sqrt{13}}\]

Answer 11

OOh , thanks a laot