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Mathematics 24 Online
OpenStudy (anonymous):

Write the sum using summation notation, assuming the suggested pattern continues. 2 - 8 + 32 - 128 + ...

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@SolomonZelman go ahead.. :)

OpenStudy (solomonzelman):

the common ratio is ? the number of term is? now think of a pattern with "n" that will generate the sequence

OpenStudy (solomonzelman):

(btw, I never liked starting with index 0)

OpenStudy (solomonzelman):

So, it appears like you have ∞ as the number of terms (on top of the Σ) in every choice. So you know what goes on top.

OpenStudy (solomonzelman):

Then on the bottom index of n=0.

OpenStudy (solomonzelman):

So, in which of the option will we get the 1st term of -2 when n=0, the 2nd term when n=1, the third term when n=2, and on ... ?

OpenStudy (solomonzelman):

You can try writing the first terms just looking at each answer choice if you want to.

OpenStudy (anonymous):

the second choice

OpenStudy (solomonzelman):

No, because you start plugging like this n=0 , 1st term n=1 , 2nd term n=2 , 3rd term and not n=1 , 1st term n=2 , 2nd term n=3 , 3rd term Since you started with an index of 0.

OpenStudy (solomonzelman):

index is the bottom of Σ

OpenStudy (anonymous):

so it would be addition, so the first choice

OpenStudy (solomonzelman):

I doubt that because you have 2, -8 AND THEN 32. It is definitely multiplication.

OpenStudy (solomonzelman):

when you took the firs attempt, you got the pattern right, \(\normalsize\color{black}{ 2(-4)^{0}}\) \(\normalsize\color{black}{ 2(-4)^{1}}\) \(\normalsize\color{black}{ 2(-4)^{2}}\) \(\normalsize\color{black}{ 2(-4)^{3}}\) and on.

OpenStudy (solomonzelman):

Which of the options generates that, (starting from n=0) ?

OpenStudy (anonymous):

C

OpenStudy (solomonzelman):

Yes, there you go !

OpenStudy (anonymous):

yayyy

OpenStudy (solomonzelman):

when you start from n=0 on the bottom of Σ, you start plugging in 0,1,2,3 and on for n. When you have n=1 on the bottom, you start plugging in 1,2,3,4 ... and on (same way, but you sart from whatever you have n equal to on the bottom of the Σ) Makes sense ?

OpenStudy (solomonzelman):

same way. but you start*

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