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Mathematics 23 Online
OpenStudy (wade123):

HELP MEDAL!!

OpenStudy (wade123):

Solve the triangle. A = 21°, C = 105°, c = 5

OpenStudy (wade123):

@robtobey

OpenStudy (wade123):

please help

OpenStudy (anonymous):

B = 180-(21+105) = 54 Use the Law of Sines to calculate the other 2 sides. http://www.mathsisfun.com/algebra/trig-sine-law.html

OpenStudy (wade123):

B = 54°, a ≈ 13.5, b ≈ 4.2 right? @robtobey

OpenStudy (wade123):

?

OpenStudy (wade123):

@cwrw238

OpenStudy (anonymous):

Recalculate a. I got a = \[a=\frac{10 \sqrt{2} \sin (21 {}^{\circ})}{1+\sqrt{3}}=1.85501 \]

OpenStudy (anonymous):

b = 4.18778

OpenStudy (wade123):

nope youre definetly wrong, none of my choices

OpenStudy (wade123):

@SithsAndGiggles please help

OpenStudy (wade123):

uhmmm?

OpenStudy (anonymous):

|dw:1408121921631:dw| \[180=B+21+105~~\iff~~B=54^\circ\] Law of sines gives \[\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}~~\iff~~\frac{\sin21^\circ}{a}=\frac{\sin54^\circ}{b}=\frac{\sin 105^\circ}{5}\] For \(a\) and \(b\) you get \[a=\frac{5\sin21^\circ}{\sin105^\circ}\approx1.855\] \[b=\frac{5\sin54^\circ}{\sin105^\circ}\approx4.188\] Getting the same as @robtobey...

OpenStudy (wade123):

whatttt. these are my choices

OpenStudy (wade123):

oops wrong one

OpenStudy (wade123):

ohh!!!!

OpenStudy (anonymous):

It's the first one. 1.855 gets rounded up to 1.9, 4.188 gets rounded to 4.2

OpenStudy (wade123):

yes! thank you so much!!!

OpenStudy (anonymous):

yw

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