Question

Convert the polar representation of this complex number into its standard form: z=6(cos300+isin300) [300 is in degrees]
HELP PLEASE

Answer 1

@johnweldon1993

Answer 2

Z = a + ib
Z = 6(cos300+isin300)

a + ib = 6(cos300+isin300)
a + ib = 6cos 300 + i . 6sin 300
= 6 cos (360 - 60) + i. 6sin (360 - 60)
= 6 cos (-60) + i . 6 sin (-60)
z = 6 cos 60 - i . 6 sin (60)

Getting this? :)

Answer 3

Okay i got that but what do u do to put it into complex form?

Answer 4

I mean standard form

Answer 5

That *is* the standard form that I solved there.

Look, standard form of a complex number (z) = A + iB

Here you are given in polar co-ordinates. Just put it in terms of A + iB [Put it in that form]

NOTE: Find cos 60 and sin 60. You'll have you answer.

Getting this?

Answer 6

So D is the correct answer right?

Answer 7

@AkashdeepDeb

Answer 8

Great job @AkashdeepDeb and yes caseyf D would be correct here, just by the fact that cos(60) = 1/2 and sin(60) = √3/2

Answer 9

Okay thank you!

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