Convert the polar representation of this complex number into its standard form: z=6(cos300+isin300) [300 is in degrees] HELP PLEASE
@johnweldon1993
Z = a + ib Z = 6(cos300+isin300) a + ib = 6(cos300+isin300) a + ib = 6cos 300 + i . 6sin 300 = 6 cos (360 - 60) + i. 6sin (360 - 60) = 6 cos (-60) + i . 6 sin (-60) z = 6 cos 60 - i . 6 sin (60) Getting this? :)
Okay i got that but what do u do to put it into complex form?
I mean standard form
That *is* the standard form that I solved there. Look, standard form of a complex number (z) = A + iB Here you are given in polar co-ordinates. Just put it in terms of A + iB [Put it in that form] NOTE: Find cos 60 and sin 60. You'll have you answer. Getting this?
So D is the correct answer right?
@AkashdeepDeb
Great job @AkashdeepDeb and yes caseyf D would be correct here, just by the fact that cos(60) = 1/2 and sin(60) = √3/2
Okay thank you!
Join our real-time social learning platform and learn together with your friends!