Question

√3 csc θ - 2 = 0

Answer 1

\[cosec \theta =2/\sqrt{3}\]
thus \[\theta =60\]

Answer 2

ok

\[\csc (\theta)=\frac{ 2 }{ \sqrt{3} }\]

\[\csc(\theta)=\frac{ a }{ b }\]
\[\sin(\theta)=\frac{ b }{ a }\]

Answer 3

so here we have
\[\sin (\theta)=\frac{ \sqrt{3} }{ 2 }\]

Answer 4

to find theta we can either look at a unit circle or do a sin^-1

Answer 5

remember
\[\sin (\theta) = \frac{ opposite }{ hypotenuse }\]

Answer 6

and in this case we have a positive value

Answer 7

so our reference angles are going to be in quadrants 1 and 2 where sin (the opposite side) is positive like so