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Can you turn this equation into vertex form?
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F(x) = x^2 - 4
its already kind of in vertex form
well doesn't it have to be (x - h)^2 - k?
yes
but in this case h is 0, and 4 is k
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It doesn't have a b variable
ya so i suppose
theres nothing to do so you cant
well let me explain, in this lesson i had to come up with a function
"one function, f(x), with two real solutions
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so i made up this function.
would that be okay? @TylerD
x^2+4x-4=0 (x+2)(x-2)=0
when x is 2 the solution is 0 when x is -2 the solution is 0 so 2 solutions
f(x)=ax^2+bx+c is standard form
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vertex form is a(x-h)^2+k
|dw:1408231667060:dw|
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