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Mathematics 10 Online
OpenStudy (anonymous):

Can you turn this equation into vertex form?

OpenStudy (anonymous):

F(x) = x^2 - 4

OpenStudy (tylerd):

its already kind of in vertex form

OpenStudy (anonymous):

well doesn't it have to be (x - h)^2 - k?

OpenStudy (tylerd):

yes

OpenStudy (tylerd):

but in this case h is 0, and 4 is k

OpenStudy (anonymous):

It doesn't have a b variable

OpenStudy (tylerd):

ya so i suppose

OpenStudy (tylerd):

theres nothing to do so you cant

OpenStudy (anonymous):

well let me explain, in this lesson i had to come up with a function

OpenStudy (anonymous):

"one function, f(x), with two real solutions

OpenStudy (anonymous):

so i made up this function.

OpenStudy (anonymous):

would that be okay? @TylerD

OpenStudy (tylerd):

x^2+4x-4=0 (x+2)(x-2)=0

OpenStudy (tylerd):

when x is 2 the solution is 0 when x is -2 the solution is 0 so 2 solutions

OpenStudy (tylerd):

f(x)=ax^2+bx+c is standard form

OpenStudy (tylerd):

vertex form is a(x-h)^2+k

OpenStudy (tylerd):

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