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Mathematics 9 Online
OpenStudy (dannyrod2000):

http://prntscr.com/4dimme

OpenStudy (dannyrod2000):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

this time you are plugging in v = 8 and g = 32. Then you solve for h

OpenStudy (dannyrod2000):

yea i got that

OpenStudy (dannyrod2000):

but i get stuck solving it

jimthompson5910 (jim_thompson5910):

show me what you have so far

OpenStudy (dannyrod2000):

\[8=\sqrt{2*32*h}\]

OpenStudy (dannyrod2000):

then what do i do?

OpenStudy (tylerd):

solve for h

OpenStudy (dannyrod2000):

do I multiply 2*32?

jimthompson5910 (jim_thompson5910):

yes you do

OpenStudy (dannyrod2000):

B?

jimthompson5910 (jim_thompson5910):

\[8=\sqrt{2*32*h}\] \[8=\sqrt{64*h}\]

jimthompson5910 (jim_thompson5910):

we need to isolate h

OpenStudy (dannyrod2000):

yea thats what i got :)

OpenStudy (dannyrod2000):

o ok

OpenStudy (dannyrod2000):

\[64=64h^2\]

OpenStudy (dannyrod2000):

1?

OpenStudy (tylerd):

yes, or you could look at it like 8=8 times h

OpenStudy (dannyrod2000):

o ok so its D?

OpenStudy (tylerd):

i dont like this problem though

OpenStudy (dannyrod2000):

\[8=8\sqrt{h}\]

jimthompson5910 (jim_thompson5910):

\[8=\sqrt{64*h}\] \[8^2=(\sqrt{64*h})^2 \ \text{ Square both sides}\] \[64=64h\]

OpenStudy (dannyrod2000):

:)

OpenStudy (dannyrod2000):

i got that :)

jimthompson5910 (jim_thompson5910):

you had h squared though

OpenStudy (dannyrod2000):

lol i still got it right

OpenStudy (dannyrod2000):

i messed up

OpenStudy (tylerd):

the setup of the problem isnt dimensionally consistent thought

jimthompson5910 (jim_thompson5910):

because squaring or square rooting 1 gives you 1 so in this case, you'll get to the same answer if you had h^2 = 4, then it'd be a different story

jimthompson5910 (jim_thompson5910):

sure it is TylerD

jimthompson5910 (jim_thompson5910):

left side is ft/sec the right side is sqrt( ft/sec^2 * ft) which leads to sqrt( ft^2/sec^2) = ft/sec

OpenStudy (dannyrod2000):

oh ok i understand :)

OpenStudy (tylerd):

oh ya

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