Mathematics
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OpenStudy (dannyrod2000):
http://prntscr.com/4dimme
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OpenStudy (dannyrod2000):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
this time you are plugging in v = 8 and g = 32. Then you solve for h
OpenStudy (dannyrod2000):
yea i got that
OpenStudy (dannyrod2000):
but i get stuck solving it
jimthompson5910 (jim_thompson5910):
show me what you have so far
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OpenStudy (dannyrod2000):
\[8=\sqrt{2*32*h}\]
OpenStudy (dannyrod2000):
then what do i do?
OpenStudy (tylerd):
solve for h
OpenStudy (dannyrod2000):
do I multiply 2*32?
jimthompson5910 (jim_thompson5910):
yes you do
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OpenStudy (dannyrod2000):
B?
jimthompson5910 (jim_thompson5910):
\[8=\sqrt{2*32*h}\]
\[8=\sqrt{64*h}\]
jimthompson5910 (jim_thompson5910):
we need to isolate h
OpenStudy (dannyrod2000):
yea thats what i got :)
OpenStudy (dannyrod2000):
o ok
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OpenStudy (dannyrod2000):
\[64=64h^2\]
OpenStudy (dannyrod2000):
1?
OpenStudy (tylerd):
yes, or you could look at it like
8=8 times h
OpenStudy (dannyrod2000):
o ok so its D?
OpenStudy (tylerd):
i dont like this problem though
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OpenStudy (dannyrod2000):
\[8=8\sqrt{h}\]
jimthompson5910 (jim_thompson5910):
\[8=\sqrt{64*h}\]
\[8^2=(\sqrt{64*h})^2 \ \text{ Square both sides}\]
\[64=64h\]
OpenStudy (dannyrod2000):
:)
OpenStudy (dannyrod2000):
i got that :)
jimthompson5910 (jim_thompson5910):
you had h squared though
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OpenStudy (dannyrod2000):
lol i still got it right
OpenStudy (dannyrod2000):
i messed up
OpenStudy (tylerd):
the setup of the problem isnt dimensionally consistent thought
jimthompson5910 (jim_thompson5910):
because squaring or square rooting 1 gives you 1
so in this case, you'll get to the same answer
if you had h^2 = 4, then it'd be a different story
jimthompson5910 (jim_thompson5910):
sure it is TylerD
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jimthompson5910 (jim_thompson5910):
left side is ft/sec
the right side is sqrt( ft/sec^2 * ft) which leads to sqrt( ft^2/sec^2) = ft/sec
OpenStudy (dannyrod2000):
oh ok i understand :)
OpenStudy (tylerd):
oh ya