Question

Calculus A help please

Answer 1

dy/dx= (3xy - y^2) / (2xy - x^3)
For vertical slope 1/0
dy/dx= (3xy - y^2) / (2xy - x^3) =1/0
(2xy - x^3)=0
x(2y-x^2)=0
x=0
y=x^2/2
x(x^2/2)^2 -x^3(x^2/2) = 6
x^5/4-x^5/2 =6
-x^5/4=6
x^5=-24
x=-0.935
y=0.437

Source: http://www.mathskey.com/question2answer/

Answer 2

Substitute y = x^2/2

Answer 3

(0,0) and (-0.935,0.437 ) are answers for c only

Answer 4

for horizontal dy/dx=0

Answer 5

for horizontal slope is zero
so dy/dx =0

Answer 6

dy/dx = (3xy - y^2) / (2xy - x^3) =0
3xy - y^2=0
y(3x-y)=0
y =0 y =3x
xy^2 -x^3y = 6
x(3x)^2 -x^3(3x) = 6
3x^3-3x^4-6=0
solve this equation