Question

Hi, I'm Deborah. I have the given equation of 2x-3y+6=0. The coordinate points given are (-3, 0) and (0, 2). I need to know how those coordinates were arrived at in order to be able to solve the other equations in my assignment. Thank you.

Answer 1

\(\large \begin{array}{ccccccll}
(-3&,&0)&(&0&,&&2)\\
x&,&y&&x&,&&y
\end{array}\)

so that means that, if we plug "x" value into the equation, "y" should be us the other value
or the other way around, if we plug in the "y" value, and solve for "x", then "x" gets given

so say....let's us try using the "x" value then \(\large 2{\color{brown}{ x}}-3y+6=0\to
\begin{cases}
2{\color{brown}{ (-3)}}-3y+6=0\to &y=\square ?
\\ \quad \\
2{\color{brown}{ (0)}}-3y+6=0\to &y=\square ?
\end{cases}\)