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Mathematics 19 Online
OpenStudy (anonymous):

whats an example of a non-extranious solution?

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

Do you know what an extraneous solution is?

OpenStudy (anonymous):

kinda im just look for a radical equation that has a non extranious solution like an example and steps

jimthompson5910 (jim_thompson5910):

let's say we had the equation sqrt(x) = -1

jimthompson5910 (jim_thompson5910):

what is the solution to that equation?

OpenStudy (anonymous):

uhh would it be -1

jimthompson5910 (jim_thompson5910):

but the square root of a negative number isn't a real number ie sqrt(-1) = a complex number (not a real number)

jimthompson5910 (jim_thompson5910):

how would you isolate x

OpenStudy (anonymous):

i dont know can you tell me (:

jimthompson5910 (jim_thompson5910):

well we have x buried in a square root we need to undo the square root to eliminate it and isolate x

jimthompson5910 (jim_thompson5910):

what undoes square rooting?

OpenStudy (anonymous):

by sqaureing a number

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

so we square both sides of sqrt(x) = -1 to get x = 1

jimthompson5910 (jim_thompson5910):

notice how squaring -1 gives us (-1)^2 = (-1)*(-1) = 1

jimthompson5910 (jim_thompson5910):

so the possible solution to sqrt(x) = -1 is x = 1

jimthompson5910 (jim_thompson5910):

however, we always should check the possible solutions sqrt(x) = -1 sqrt(1) = -1 ... replace x with 1 1 = -1 ... this is false, so x = 1 is NOT a true solution

jimthompson5910 (jim_thompson5910):

so we call x = 1 an extraneous solution it popped up in the process of solving for x, but it's not a true solution to the *original* equation

OpenStudy (anonymous):

oh ok so no im confused i was looking for a non-extranious

jimthompson5910 (jim_thompson5910):

I know. I'm setting things up and defining what an extraneous solution is.

OpenStudy (anonymous):

oh ok so now i understand the extranous way now i need to understand the non extranous

jimthompson5910 (jim_thompson5910):

now if we made the right side positive, say +4, then we'll have this equation sqrt(x) = 4 squaring both sides gives you x = 16 so the *possible* solution to sqrt(x) = 4 is x = 16 we always need to check things though sqrt(x) = 4 sqrt(16) = 4 ... replace all copies of x with 16, the supposed solution 4 = 4 ... this equation is true Because x = 16 satisfies the *original* equation, this confirms x = 16 to be a true solution to sqrt(x) = 4. So x = 16 is considered non-extraneous

jimthompson5910 (jim_thompson5910):

extraneous solutions don't satisfy the original equation non-extraneous solutions do satisfy the original equation both are generated in the process of solving for x

OpenStudy (anonymous):

ohhh ok now i get it. ok thank you for explaing so well (:

jimthompson5910 (jim_thompson5910):

you're welcome

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