Question

a football is thrown with an initial upward velocity component of 15 m/s and a horizontal velocity component of 18 m/s. Ignore air resistance.
a. how much time is required for the football too reach the highest point of the trajectory?
b. how much time is required for the football to return to its original level?
thanks :)

Answer 1

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Answer 2

Since initial upward velocity is 15 m/s, time taken to reach the highest point t can be calculated by using equation v=u+at.
Here,
u=15m/s
a=-9.8m/\(\sf s^2\)
v=0

\(\sf \Rightarrow 0=15-9.8\times t\\ \Rightarrow t=1.53~seconds\)

Answer 3

Time required to reach the same level will be double the time required to reach the highest level = 2t \(\approx\)3 seconds