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Chemistry 8 Online
OpenStudy (anonymous):

NEED HELP, TAKING A FINAL EXAM!! If the quantity of H3O+ ions in a solution is equal to the quantity of OH- ions, what would be the pH value? Answer 1 4 7 11

OpenStudy (anonymous):

7

OpenStudy (anonymous):

A solution has a [OH-] of 1 × 10-12. What is the pOH of this solution? Answer 2 7 10 12

OpenStudy (anonymous):

We know the formula for pOH to be \[pOH = -\log[OH^-]\] So if you take the negative log of 1E-12, you'll get the pOH.

OpenStudy (anonymous):

can you show the steps?

OpenStudy (anonymous):

Really you can just use a calculator lol

OpenStudy (anonymous):

all i have is the plain pelletty one on the computer lol

OpenStudy (anonymous):

excuse my language.

OpenStudy (anonymous):

nvm...

OpenStudy (anonymous):

Alright, I'll skip explaining how to manually calculate logs lol It's 12. In 99.9% of circumstances when doing chemistry you'll have a calculator and you can just type -log(1x10^-12)

OpenStudy (anonymous):

yeah i have just misplaced my calculator and dont have the log sin or tan buttons. verysimple one tonight my friend.

OpenStudy (anonymous):

In compounds, what is the oxidation number of group VIIA compounds? Answer 1- 3 + 5 + 7 +

OpenStudy (anonymous):

Group VIIA being halogens, correct?

OpenStudy (anonymous):

i only have a few more questions, will you help me finish so i can pass and you can get on your way lol

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

I don't mind helping. I like chemistry. Halogens are really close to an octet, and want one electron really bad. They're all -1 normally.

OpenStudy (anonymous):

alright next one lol What is the oxidation number of O in H2O2? Answer -2 -1 +1 0

OpenStudy (anonymous):

Oxygen is normally -2, but H2O2 is the exception. It's -1.

OpenStudy (anonymous):

is it 1?

OpenStudy (anonymous):

oh nvm haha

OpenStudy (anonymous):

getting a little tougher now What is the oxidizing agent in the following equation? Al (s) + 3 Ag+ (aq) → Al+3 (aq) + 3 Ag (s) Answer Al (s) Ag+ (aq) Al+3 (aq) Ag (s)

OpenStudy (anonymous):

The oxidizing agent is the thing that accepts the electron. We see that Al goes from 0 to +3, meaning it lost 3 electrons. By deduction we then know that Ag was reduced and is the oxidizing agent.

OpenStudy (anonymous):

It's Ag+ as it was reduced to Ag

OpenStudy (anonymous):

As aq or Ag s?

OpenStudy (anonymous):

Aqueous

OpenStudy (anonymous):

2 more To balance the following half-reaction, Cr3+ → CrO4-, how many waters need to be added? Answer 4 waters to the product side 2 waters to the product side 4 waters to the reactant side 2 waters to the reactant side

OpenStudy (anonymous):

How are voltaic cells and electrolytic cells similar? Answer Both occur due to spontaneous reactions. Both require the input of energy. Both have a negative charge on the anode. Both cells use oxidation-reduction reactions.

OpenStudy (anonymous):

Alright, I'll answer one at atime

OpenStudy (anonymous):

alright..

OpenStudy (anonymous):

For the first one, you'd need 4 H2O to the reactants side.

OpenStudy (anonymous):

thats what i thought but i would rather be safe than sorry, alright the last one now

OpenStudy (anonymous):

And both types of cells do redox reactions.

OpenStudy (anonymous):

oxidation reduction?

OpenStudy (anonymous):

yes

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