NEED HELP, TAKING A FINAL EXAM!! If the quantity of H3O+ ions in a solution is equal to the quantity of OH- ions, what would be the pH value? Answer 1 4 7 11
7
A solution has a [OH-] of 1 × 10-12. What is the pOH of this solution? Answer 2 7 10 12
We know the formula for pOH to be \[pOH = -\log[OH^-]\] So if you take the negative log of 1E-12, you'll get the pOH.
can you show the steps?
Really you can just use a calculator lol
all i have is the plain pelletty one on the computer lol
excuse my language.
nvm...
Alright, I'll skip explaining how to manually calculate logs lol It's 12. In 99.9% of circumstances when doing chemistry you'll have a calculator and you can just type -log(1x10^-12)
yeah i have just misplaced my calculator and dont have the log sin or tan buttons. verysimple one tonight my friend.
In compounds, what is the oxidation number of group VIIA compounds? Answer 1- 3 + 5 + 7 +
Group VIIA being halogens, correct?
i only have a few more questions, will you help me finish so i can pass and you can get on your way lol
yes
I don't mind helping. I like chemistry. Halogens are really close to an octet, and want one electron really bad. They're all -1 normally.
alright next one lol What is the oxidation number of O in H2O2? Answer -2 -1 +1 0
Oxygen is normally -2, but H2O2 is the exception. It's -1.
is it 1?
oh nvm haha
getting a little tougher now What is the oxidizing agent in the following equation? Al (s) + 3 Ag+ (aq) → Al+3 (aq) + 3 Ag (s) Answer Al (s) Ag+ (aq) Al+3 (aq) Ag (s)
The oxidizing agent is the thing that accepts the electron. We see that Al goes from 0 to +3, meaning it lost 3 electrons. By deduction we then know that Ag was reduced and is the oxidizing agent.
It's Ag+ as it was reduced to Ag
As aq or Ag s?
Aqueous
2 more To balance the following half-reaction, Cr3+ → CrO4-, how many waters need to be added? Answer 4 waters to the product side 2 waters to the product side 4 waters to the reactant side 2 waters to the reactant side
How are voltaic cells and electrolytic cells similar? Answer Both occur due to spontaneous reactions. Both require the input of energy. Both have a negative charge on the anode. Both cells use oxidation-reduction reactions.
Alright, I'll answer one at atime
alright..
For the first one, you'd need 4 H2O to the reactants side.
thats what i thought but i would rather be safe than sorry, alright the last one now
And both types of cells do redox reactions.
oxidation reduction?
yes
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