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Mathematics 8 Online
OpenStudy (anonymous):

Help me with factoring question!

OpenStudy (anonymous):

Factor the sum or difference of cubes

OpenStudy (anonymous):

\[X^2-\frac{ 8 }{ 27 }\]

OpenStudy (math&ing001):

That should be : x^3 - 8/27.

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

My bad

OpenStudy (anonymous):

Can you teach me step by step on how to do this?

OpenStudy (math&ing001):

You know about the formula a^3 - b^3 ?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

I didn't know there was a formula

OpenStudy (math&ing001):

If you don't know it you can't factor that expression.

OpenStudy (anonymous):

Can you teach me it? I really want to learn this, so I don't have trouble in the future

OpenStudy (math&ing001):

Ok I'll give you the formula and you'll have to apply it in this case. a3 – b3 = (a – b)(a2 + ab + b2)

OpenStudy (anonymous):

Ok

OpenStudy (math&ing001):

\[x ^{3} - \frac{ 8 }{ 27 } = x ^{3} - (\frac{ 2 }{ 3 })^{3}\] Take a=x and b=2/3 and apply the formula.

OpenStudy (anonymous):

Ok. I saw someone in my class do it similarly. Only they did it like this\[\frac{ x^3 * 27 - 8}{ 27 }\]

OpenStudy (anonymous):

Then they did multiplied the 27 by the x^3

OpenStudy (anonymous):

to get \[\frac{ 27x^3 - 8 }{ 27 }\]

OpenStudy (math&ing001):

Are you asked to find the common denominator or to factor ??

OpenStudy (anonymous):

Factor

OpenStudy (anonymous):

I just wanted to see if there were different ways to do it.

OpenStudy (anonymous):

Sorry if I confused you.

OpenStudy (math&ing001):

Well what you did there was find the common denominator, that is not how to factor.

OpenStudy (anonymous):

Ok.

OpenStudy (math&ing001):

\[x ^{3}-\frac{ 27 }{ 8 }=x ^{3}-(\frac{ 2 }{ 3 })^{3}=(x-\frac{ 2 }{ 3 })(x ^{2}+\frac{ 2 }{ 3 }x+\frac{ 4 }{ 9 })\] That's how you factor.

OpenStudy (anonymous):

Is that all?

OpenStudy (anonymous):

Ok. That is what I got.

OpenStudy (anonymous):

Thanks so much.

OpenStudy (math&ing001):

Welcome !

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