Mathematics
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OpenStudy (anonymous):
Help me with factoring question!
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OpenStudy (anonymous):
Factor the sum or difference of cubes
OpenStudy (anonymous):
\[X^2-\frac{ 8 }{ 27 }\]
OpenStudy (math&ing001):
That should be : x^3 - 8/27.
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
My bad
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OpenStudy (anonymous):
Can you teach me step by step on how to do this?
OpenStudy (math&ing001):
You know about the formula a^3 - b^3 ?
OpenStudy (anonymous):
No
OpenStudy (anonymous):
I didn't know there was a formula
OpenStudy (math&ing001):
If you don't know it you can't factor that expression.
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OpenStudy (anonymous):
Can you teach me it? I really want to learn this, so I don't have trouble in the future
OpenStudy (math&ing001):
Ok I'll give you the formula and you'll have to apply it in this case.
a3 – b3 = (a – b)(a2 + ab + b2)
OpenStudy (anonymous):
Ok
OpenStudy (math&ing001):
\[x ^{3} - \frac{ 8 }{ 27 } = x ^{3} - (\frac{ 2 }{ 3 })^{3}\] Take a=x and b=2/3 and apply the formula.
OpenStudy (anonymous):
Ok. I saw someone in my class do it similarly. Only they did it like this\[\frac{ x^3 * 27 - 8}{ 27 }\]
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OpenStudy (anonymous):
Then they did multiplied the 27 by the x^3
OpenStudy (anonymous):
to get \[\frac{ 27x^3 - 8 }{ 27 }\]
OpenStudy (math&ing001):
Are you asked to find the common denominator or to factor ??
OpenStudy (anonymous):
Factor
OpenStudy (anonymous):
I just wanted to see if there were different ways to do it.
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OpenStudy (anonymous):
Sorry if I confused you.
OpenStudy (math&ing001):
Well what you did there was find the common denominator, that is not how to factor.
OpenStudy (anonymous):
Ok.
OpenStudy (math&ing001):
\[x ^{3}-\frac{ 27 }{ 8 }=x ^{3}-(\frac{ 2 }{ 3 })^{3}=(x-\frac{ 2 }{ 3 })(x ^{2}+\frac{ 2 }{ 3 }x+\frac{ 4 }{ 9 })\] That's how you factor.
OpenStudy (anonymous):
Is that all?
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OpenStudy (anonymous):
Ok. That is what I got.
OpenStudy (anonymous):
Thanks so much.
OpenStudy (math&ing001):
Welcome !