1. The genes A/a, B/b, C/c, D/d, are located on four different chromosomes. If an
individual heterozygous for all four genes undergoes meiosis, the frequency of
gametes of genotype abcd will be:
a) 0.031
b) 0.062
c) 0.125
d) 0.250

Question

1. The genes A/a, B/b, C/c, D/d, are located on four different chromosomes. If an 
individual heterozygous for all four genes undergoes meiosis, the frequency of 
gametes of genotype abcd will be: 
a) 0.031 
b) 0.062 
c) 0.125 
d) 0.250

kamille · Answer

@KlOwNlOvE

kamille · Answer

@abb0t

aaronq · Answer

If they're on different chromosomes, then they are not linked and they follow mendelian genetics (i.e. independent assortment).

kamille · Answer

So basically all I need to do, is AaBbCcDd x AaBbCcDd and find the percentage (probability)? @aaronq

kamille · Answer

I didn't finish - flutter - I am sorry, the probability of aabbccdd?

aaronq · Answer

yep exactly. 

you can even simplify it, you know that in every cross Aa x Aa,  you'l have 0.25 aa, right?

it happens for every gene so, $\sf P(aabbccdd)=(0.25)^4$

kamille · Answer

thanks: }

aaronq · Answer

no problem!