Question

@satellite73 @ganeshie8

Answer 1

What is your question?

Answer 2

Solve. \[\log_{4} \sqrt{8} =\]

Answer 3

there is supposed to be an X after the equals sighn

Answer 4

x is not important

this is asking 'what power do you raise 4 to, to give you 8
i.e. is asking "solve for \(x\), \(4^x=8\)

Answer 5

oh square root of 8 sorry
\[4^x=\sqrt{8}\]

Answer 6

I got 2.82842712 for the square root of 8

Answer 7

they want you to recognize both as powers of 2
\[4^x=2^{2x}\]
\[\sqrt{8}=\sqrt{2^3}=2^{\frac{3}{2}}\]

Answer 8

this is not a calculator exercise

Answer 9

\[\large 2^{2x}=2^{\frac{3}{2}}\iff 2x=\frac{3}{2}\]

Answer 10

is that the answer

Answer 11

lol no you have to solve
\[\large 2x=\frac{3}{2}\] for \(x\)

Answer 12

ok how?

Answer 13

I would multiply both sides by 2 to make them wholes

Answer 14

4x = 3

Answer 15

if you wanted to use a calculator to solve this, you can
you type in
\[\log(\sqrt8)\div\log(4)\] and you will get it

Answer 16

Oh, haha c;

Answer 17

@ShadowLegendX no ! divide by 2 and get
\[x=\frac{3}{4}\]

Answer 18

thank you soo much I appreciate it

Answer 19

yw

Answer 20

Ok, good job @satellite73