Find the Domain of f(x)= e^√((x+2)/(x^2-1))

My working is as follows
f(x)= e^√((x+2)/(x^2-1))
√((x+2)/(x^2-1))≥0
x^2-10
x^21
x1
D:All real numbers1

However when I graph the function, x can be equal to -2?

Question

Find the Domain of f(x)= e^√((x+2)/(x^2-1))

My working is as follows
f(x)= e^√((x+2)/(x^2-1))
√((x+2)/(x^2-1))≥0
x^2-1>0
x^2>1
x>1
D:All real numbers>1


However when I graph the function, x can be equal to -2?

anonymous · Answer

hold the phone

anonymous · Answer

your job it to solve 
$$\frac{x+2}{x^2-1}\geq 0$$

anonymous · Answer

two mistakes here in your calculation
you ignored the $x+2$in the numerator, and $$x^2-1>0\x^2>1\x>1$$ is not correct

anonymous · Answer

the second mistake is less important than the first one, since you have to solve $$\frac{x+2}{x^2-1}\geq 0$$ in any case

anonymous · Answer

I think I understand what you're saying, thank you.

anonymous · Answer

yw

anonymous · Answer

Could you elaborate a little further on the second mistake, how would I find the domain of x^2-1>0?

anonymous · Answer

Also if my $$x \ge 2$$
then my denomiator could be equal to zero?

anonymous · Answer

-2*