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predict the chemical formula of butyne, having one carbon-carbon triple bond
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The general formula for an alkane is: \(\sf \color{red}{C_nH_{2n+2}}\) If you make a double-bond, you're subtracting 2 protons, so then you have for an alkene: \(\sf \color{blue}{C_nH_{2n-2}}\) and if you form a triple bond, that means 4 proton are missing, and you have: \(\sf \color{orange}{C_nH_{2n-4}}\)
No. when you subtract 2 protons from CnH2n+2, you get CnH2n, and when you subtract 4 protons you get CnH2n-2
You're absoltely right. Thank you for correcting me.
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