Factoring by grouping
2x^2+4-2

Question

Factoring by grouping
2x^2+4-2

anonymous · Answer

Is it $$2x ^{2}+4x-2$$
or just $$2x^{2}+4-2$$

anonymous · Answer

sorry, its the first one

anonymous · Answer

sorry, i made you wait so long but this can't be factored by grouping..

anonymous · Answer

so would that make it 2 complex solutions or 2 irrational solutions

campbell_st · Answer

I still think there is an error as the expression can't be grouped in pairs to factor... the only common factor is 2

then its 

2(x^2 + 2x -1)

anonymous · Answer

Well the section im in is factoring by grouping but it says to predict the solutions
a. two rational solutions
b.one rational solution
c. two irrational solutions
d. two complex solutions

campbell_st · Answer

use the discriminant to determine the nature of the roots

anonymous · Answer

-b-4ac? 
2x^2+4x-2
(4)^2 -4(2)(-2)
16-8(-2)
16-16
0
right?

campbell_st · Answer

well almost

16 - 4(2)(-2) = 16 + 16
                    = 32

so the roots are real and irrational...

anonymous · Answer

you saved my life!