OpenStudy (anonymous):
A golf ball released from a height of 1.50 m above a concrete floor, bounces back to a height of 1.02 m. If the ball is in contact with the floor for 5.11 ms, what is the magnitude of the average acceleration a of the ball while it is in contact with the floor?
OpenStudy (anonymous):
Use the fact that the ball's potential energy is converted into kinetic energy on the way down, and vice versa on the way back up, to calculate the balls speed going into, and coming out of the collision with the floor. The average acceleration is then the change in speed during the collision divided by the collision time given in the question. Note that the ball doesn't climb as high coming out of the collision, so it exits with less kinetic energy than it had going into the collision.
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