let f(x)= ln(3+sin x) is f periodic? if so what is its period? please explain.
thank you for helping me
No problem
as you can see this question looks like Chinese.
It makes sense, but the ln makes the situation complicated. The bit within the () is periodic, I have to double check on the ln
First of all, you understand what it wants by period, right?
yes. and I thought you need the formula 2pi/b but I don't see can b in this.
In this situation, I'm positive that the b=1, because there isn't any sort of coefficient directly in front of the x in sinx
First, we need to determine whether the ln removes it from a periodic equation.
looks periodic to me
That it does, so the period in this case appears to be 0-6.25
what?
how did u come to that conclusion
One moment, let me get the image
Do you understand?
0-6.25 is the period based on what info in that chart
Just the change in y from 0 to 6.25. Just eyeballing it, from my starting point at x=0, at x=6.25, the line of the graph appears to have returned to the same y position after having performed one loop of the equation. Does that make sense?
yes. thanks so much.
\(\sin x\) is \(2\pi\)-periodic, and so is \(3+\sin x\). \(\ln x\) is defined for positive values of \(x\), which is true for \(3+\sin x\), since \(2\le3+\sin x\le4\). This means the function retains its periodicity.
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