Question

factorise x^2-4xy+4y^2

Answer 1

\[x^2-4xy+4y^2=x^2-4xy+(2y)^2\]
By \[a^2+2ab+b^2=(a+b)^2\],
\[x^2-4xy+4y^2=x^2-4xy+(2y)^2=(x-2y)^2\]

Answer 2

I've never heard of "factorise."

Answer 3

Factor the following:
\(x^2-4 x y+4 y^2\)
Factor the quadratic \(x^2-4 x y+4 y^2\)
The factors of 4 that sum to -4 are -2 and -2. So, \(x^2-4 x y+4 y^2 = (x-2 y) (x-2 y):\)
\[(x-2 y) (x-2 y) \]Combine products of like terms.
\[(x-2 y) (x-2 y) = (x-2 y)^2: \]

Answer 4

Which leaves you with..?

Answer 5

Thanks guys.