Question

Find the acceleration?

Answer 1

A velocity–time graph for an object moving along the x axis is shown in the figure. Every division along the vertical axis corresponds to 2.00 m/s and each division along the horizontal axis corresponds to 2.50 s.

Answer 2

Determine the average acceleration of the object in the time interval
t = 12.5 s
to
t = 37.5 s.

Answer 3

Do you have the figure of which you speak?

Answer 4

I have the velocity graph. Let me screen shot. I assume I need delta v/ delta t?

Answer 5

It looks to me like between (0,0) and (0,-8), there is not acceleration cuz the line is flat, no slope. Between (2.5, -8) and ( 7.5, 8) is where your acceleration is. Find the slope between those 2 points, is my best guess.

Answer 6

After x = 7.5 it doesn't appear that the acceleration is increasing, only staying the same.

Answer 7

since it says average acceleration and you are given the velocity graph
then use the slope formula for (12.5,v(12.5)) and (37.5,v(37.5))

Answer 8

Ok. Thanks all! I over complicate things!

Answer 9

the same thing you would do with average rate of change
except you will look at the position graph and find the slope

Answer 10

I wonder if this will give the same answer as IMstuck

Answer 11

Alright, so looking for the average acc from 12.5 to 37.5, I need to take the deltas, correct?