Question

Just I am recalling it:

Don't reply to it, until I permit.. :)

Answer 1

\[\frac{\sec(x) cosec(90-x) - \tan(x) \cot(90-x) + (\sin^2(35^{\circ}) + \sin^2(55 ^{\circ})) }{\tan(10) \tan(20)\tan(45)\tan(70)\tan(80)}\]

Answer 2

\(cosec(90-x) = sec(x)\)

\(cot(90-x) = tan(x)\)

Answer 3

\[\frac{\sec^2(x) - \tan^2(x) + (\sin^2(90-55) + \sin^2(55))}{\tan(90-80)\tan(90-20)\tan(45) \tan(70)\tan(80)}\\ \\ \frac{1 + (\cos^2(55) + \sin^2(55))}{\cot(80) \cot(70) \tan(45) \tan(70) \tan(80)}\\ \frac{1 + 1}{1} \\ \implies \color{blue}{2}\]

Answer 4

90 degree hai

Answer 5

Where??

Answer 6

there?

Answer 7

yes..

Answer 8

Do you have that pic with you in laptop??

Answer 9

Hello..

Answer 10

I am logging out..

If you want to send that pic, then you can attach here or you can send on facebook..

Just below this comment box, there is button named as"Attach File" just click that and attach it..

Answer 11

Are you sleeping earlier?? :P

Answer 12

yesss

Answer 13

can you explain something

Answer 14

Question ??

Answer 15

Ma'm, tell me the question number.. :P

Answer 16

sec2(x)−tan2(x)+(sin2(90−55)+sin2(55))tan(90−80)tan(90−20)tan(45)tan(70)tan(80)1+(cos2(55)+sin2(55))cot(80)cot(70)tan(45)tan(70)tan(80)

Answer 17

ye kaise aaya tha..

Answer 18

Dobara type karo..

Answer 19

12 nuber hai qusetion ka..
going for dinner tum bhi joa padh lo

Answer 20

Kya kaise aaya tha?/ Time par nahin puchh sakti kya tum??

Answer 21

arey matlab usko dusre method se karay haia b aa gya use dusre method se :)

Answer 22

tan(90-80) = cot(80)
tan(90-70) = cot(70)

sec^2(x) - tan^2(x) = 1
sin^2(90-55) = cos^2(55)

cos^2(55) + sin^2(55) = 1

tan(60) = sqrt{3}

tan(45) = 1

cot(80)tan(80) = 1
cot(70)tan(70) = 1

Answer 23

Now ask what you want to ask..

Answer 24

par thoda jaldi puchho aur thoda jaldi reply bhi karo..

Answer 25

tan(10) hai na??

10 ko main likh sakta hu : 90-80 ??

to hua : tan(90-80)

Answer 26

tan(90-x) = cot(x)

So: tan(90-80) = cot(80). getting??

Answer 27

haan wo samjh me aya fir next wala 90-70

Answer 28

same waise hi:

tan(20) hai na:

tan(90-70) = cot(70)..

Answer 29

Ab yeh nahin puchhogi kyon kiya hai aise??

Answer 30

haan kyu ? usko ye method nhi btaya hai to meri sun ne ko tyar nhi hai :(

Answer 31

90-20 likha hai tumne?

Answer 32

Kyonki tum jaanti ho ke tan(x) cot(x) = 1, because they are reciprocal of each other..

But x needs to be same value here..

tan(10) cot(80) \(\ne\) 1

cot(80)tan(80) = 1

Answer 33

neeche tumhare paas hai : tan(10)tan(80)

Convert anyone to cot.. Suppose you want to convert tan(80) then:

tan(80) = tan(90-10) = cot(10)

Answer 34

ok

Answer 35

so: tan(10)tan(80) = tan(10)cot(10) = 1

Answer 36

Jaise marji kar sakti ho tum..

Answer 37

similarly : tan(20)tan(70) = tan(20)cot(20) = 1..

So : neeche denominator me sirf tan(60) reh jaaega.. jiski value \(\sqrt{3}\) hoti hai..

Answer 38

Upar Identities use ki hain:

\(sin^2(x) + cos^2(x) = 1\) hota hai..

\(sec^2(x) - tan^2(x) = 1\) hota hai..

Answer 39

idhar dekho:

sin^2(35) = sin^2(90-55) = cos^2(55) becuase \(sin(90-x) = cos(x)\)

Answer 40

acha ab bas karo wrna mai apna subject bhul jaungi :(

Answer 41

Aur kahin doubt hai ji??

Answer 42

nhi.. sab upar se gya :(

Answer 43

Kya samajh nahin aaya??

Answer 44

Dekho yeh sab Manisha ka hai vo padh rahi agar main usse directly interact karunga to hi usey samajh me aa paaega.. :(

Answer 45

okay

Answer 46

par tumhe mai interact krne nhi dungi :)