Question

Halving the Kelvin temperature of a gas in a rigid container decreases the gas pressure by one half.
A. True
B. False
@Somy

Answer 1

i think its true

Answer 2

well prove it
i'll give you the initial formula and u play with it and see what u get
k?

so
PV=nRT
here u go
make pressure as a subject and see what you get

Answer 3

when you use pressure in a sequence like this, with no numbers i get kinda confuzzled

Answer 4

hmm so u can't play with a formula when it has no numbers?

Answer 5

it messes me up a tad

Answer 6

okaaay actually u should learn to do it this way as its actually muuuuuch easier
look

\(\huge P\times V = n \times R \times T\)
this is how you initially see it
so imagine they are numbers
what would you do if you want ONLY P on the left side?

you would divide nRT BY V right?

so
\(\huge P = \frac {n \times R \times T}{V}\)

Answer 7

so now can you try it but this time make T as subject?

Answer 8

PV=nRT and nRT=PV is exactly same thing so do like i did

Answer 9

so its false?

Answer 10

try it
you'll see

Answer 11

look a the formula
P= nRT/V
if you were to halve T which means T/2
wouldn't your Pressure also decrease?
just take a look at it

Answer 12

as the temperature of an enclosed gas decreases, the particles move more slowly and have less kinetic energy. They strike the container walls with less force. Halving the Kelvin temperature of a gas in a rigid container decreases the gas pressure by half.
P1/T1=P2/T2
P1=1 atm T1=298 Kelvin T2=149 P2=??
P2=149*1/298=0.5
so the statement is true